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Q: Which will have the greater acceleration rolling down the incline a bowling ball or volleyball?

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If they are both solid, and the incline is the same, the rate of acceleration will be the same.

The acceleration due to gravity remains constant, regardless of incline. The fact that it is on an incline does not change the fact that it will remain constant, it will only change the component of that acceleration being applied to the ball.

The acceleration of a tennis ball rolling down an incline depends with two factors. The force that is applied to the tennis ball and the mass of the tennis ball will determine its acceleration.

with a speed gun

The contribution of the acceleration of gravity in the direction of motion increases as the angle of the incline increases. Or in other words, as the angle between the direction of motion and the force of gravity goes to zero, the acceleration of the object goes to the gravitational acceleration. a = g cos(theta) Where theta is the angle between the direction of motion and verticle, which is in fact (theta = 90 - angle of the incline)Where a is the acceleration of the object down the incline plane and g is the acceleration due to gravity. Theta is the angle between the direction of motion of the accelerating object and the acceleration of gravity. Initially, the angle between a and g is 90 degrees (no incline) and therefore g contributes nothing to the objects acceleration. a = g cos(90) = 0 As the angle of the inclined is increased, the angle between a and g approaches zero, at which point a = g. With no other forces acting upon the object, g is its maximum acceleration.

There is an optimal distance at which space dominoes fall the fastest. When a domino is tipped on it's side, the greater the angle of incline, the greater the acceleration. However, it takes more time for the domino to get to a greater angle of incline. When the dominoes are closer, the dominoes impact each other at a higher spot, leading to more rotational momentum. The exact optimal distance, depends various factors including the friction between the dominoes and the floor.

The higher the incline plane, the greater the angle made between the plane and the horizontal. So the plane will be steeper.

The car experiences greater acceleration from a steeper incline (i.e. you added energy to the system by raising the ramp). The car can then go further due to the increased force (F=ma).

Extrapolate the experimental values of acceleration, vs. angle of the incline, to find the acceleration when the angle of inclination = 90 degrees. The acceleration at 90 degrees will equal 9.81 m/s/s, since this is the free-fall acceleration.

Yes. The acceleration is directly proportional to the objects mass.For objects with constant mass however, the acceleration will remain constant.

i am the one asking the question

I assume you are asking this in regards to an inclined plane so I will answer it accordingly, Well Recall the equation Force = Mass x Acceleration. In the case of free falling objects Acceleration is equal to gravity, however, on an inclined plan the presence of an incline prevents the object from falling straight down. Instead it must accelerate with some component of gravity. Now recall that perpendicular forces of action on an Incline plane are calculated by Sin theta and that perpendicular forces ( the normal force) is calculated by Cos theta Hence because the object is accelerating down an incline the formula for its total force parallel to the object would be Force = mg sin theta Now if you remember, if you simply remove the mass from the above equation you will be left with the acceleration component of the problem ala the force = mass x acceleration formula. So gsintheta represents A ( acceleration) in the Force = mass times acceleration formula.

Objects accelerating is a changing in how fast a object is moving. Acceleration is caused by gravities force when a object is dropped or on a incline.

I have no clue.

If the angle of incline or distance is greater yes.

Depends what u mean by that. If it is free falling it would obviously be accelerating at 9.8m/s^2. If there is an incline then it depends. I believe acceleration is directly proportional to velocity though.

If you mean using a longer incline to reach the same height, the answer is no. Energy is the ability to do work. Work = Force x distsance. A longer incline will require less force, but since the distance is greater the total energy stays the same.

Your mass times the acceleration due to gravity times the sine of the angle of the incline

No. Each is independent of the the other. However actual acceleration a in a given direction is dependent solely on ramp angle i.e. a= g x cosin(theta). Note that one is assuming a constant acceleration due to gravity (g).

For uniform acceleration the average speed is the initial speed plus the final speed divided by two.

The disk because it has a lower moment of inertia for a given mass.

Newtons second law of motion, describes the relationship between force, mass and acceleration: f = m * a , ( a = f / m ), ( m = f / a ) > Inclined plane: The force (kgf) down the incline on a body on an inclined plane is = mass (kg) * (sin (incline angle)) So if you change the mass, the force down the incline changes in proportion, the acceleration will remain the same, regardless of changes in mass.

.281 meters

From f = m*a, a = f/m, so if the force remains constant and the mass increases, the acceleration will decrease. But if the block is on an incline and the force is provided by gravity, the force will increase directly proportional to the mass of the block, and acceleration will remain the same.

y=mx+b This is the slope intercept form of an equation. y is the dependent variable m is the slope x is the independent variable b is the y-intercept To answer your question, the slope (m) is the rise/run of the equation. It describes the steepness, incline, or grade of a line. The higher the slope, the greater the incline. The lower the slope, the slower the incline. If the slope is a negative, then the line will be at a decline. The greater a negative number the slope is, the greater the decline.